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AEE Certified Energy Manager (CEM) Sample Questions (Q32-Q37):
NEW QUESTION # 32
An air-conditioning unit delivers 10,000 kJ/h (thermal cooling). The equipment uses single-phase electrical power at 220-volt and 5.25 amps with a power factor of 100%. Calculate the coefficient of performance (COP).
- A. 13.2
- B. 3.2
- C. 2.4
- D. 16.1
- E. 6.2
Answer: B
Explanation:
A screenshot of a computer AI-generated content may be incorrect.
NEW QUESTION # 33
An energy-saving project costs $540,000. The project will have maintenance costs of $25,000 per year. The energy savings from the project are $160,000 per year. What is the simple payback of the project?
- A. 2.0 years
- B. 4.0 years
- C. 5.0 years
- D. 3.0 years
Answer: B
Explanation:
To determine the simple payback period for the energy-saving project, we need to apply the standard formula used in energy management as per the Association of Energy Engineers (AEE) Certified Energy Manager (CEM) guidelines. The simple payback period is a widely used metric in energy efficiency projects to evaluate how long it takes for the initial investment to be recovered through net savings. Let's break this down step-by-step using the provided data and CEM-aligned methodology.
Step 1: Understand the Simple Payback Formula
* Formula: Simple Payback Period (years)=Initial Investment CostNet Annual Savings ext{Simple Payback Period (years)} = rac{ ext{Initial Investment Cost}}{ ext{Net Annual Savings}} Simple Payback Period (years)=Net Annual SavingsInitial Investment Cost
* Definition: The simple payback period represents the time (in years) required for the cumulative savings to equal the initial investment, without considering the time value of money (e.g., discount rates or inflation).
* CEM Reference: AEE CEM training materials emphasize this formula in the "Energy Economics" section, where simple payback is a fundamental tool for assessing project feasibility.
Step 2: Identify Given Data
* Initial Investment Cost: $540,000 (one-time cost of the project).
* Annual Energy Savings: $160,000 per year (benefit from the project).
* Annual Maintenance Costs: $25,000 per year (additional cost incurred due to the project).
* Net Annual Savings: This must account for both the savings and the costs incurred annually.
Step 3: Calculate Net Annual Savings
* Definition: Net annual savings is the difference between the annual energy savings and any additional annual costs (e.g., maintenance).
* Verification: The problem specifies maintenance costs as an ongoing expense tied to the project, which reduces the effective savings. CEM guidelines require including such costs in payback calculations unless explicitly stated otherwise.
Step 4: Compute the Simple Payback Period
* Apply the Formula: Simple Payback Period=Initial Investment CostNet Annual Savings ext{Simple Payback Period} = rac{ ext{Initial Investment Cost}}{ ext{Net Annual Savings}} Simple Payback Period=Net Annual SavingsInitial Investment Cost Simple Payback Period=540,
000135,000=4.0 years ext{Simple Payback Period} = rac{540,000}{135,000} = 4.0 , ext{years} Simple Payback Period=135,000540,000=4.0years
* Result: The payback period is exactly 4.0 years, meaning it takes 4 years for the net savings to recover the initial investment.
Step 5: Validate Against Options
* Options:A. 2.0 yearsB. 3.0 yearsC. 4.0 yearsD. 5.0 years
* Check:
* If we ignored maintenance costs (incorrectly), payback would be 540,000160,000=3.375 rac
{540,000}{160,000} = 3.375 160,000540,000=3.375 years, which rounds to 3.4-not an exact match for any option.
* With maintenance costs included, 540,000135,000=4.0 rac{540,000}{135,000} = 4.0
135,000540,000=4.0, which matches option C precisely.
* Conclusion: Option C (4.0 years) is correct based on the net savings approach.
NEW QUESTION # 34
For general indoor residential lighting applications, which lamp would you recommend to replace an 11 watt CFL with in order to provide the most appropriate illumination with the highest efficacy?
SELECT THE CORRECT ANSWER
- A. 4 watt incandescent
- B. 7 watt light-emitting diode
- C. 36 watt fluorescent tube with electronic ballast
- D. 10 watt light-emitting diode
- E. 5 watt low-pressure sodium
Answer: B
NEW QUESTION # 35
What does a manometer measure?
- A. Volume
- B. Distance
- C. Voltage
- D. Pressure
Answer: D
Explanation:
Amanometeris used to measurepressure, particularly in gases and liquids.
Step 1: Analysis of Each Option
* Pressure (A):#Correct. Manometers are commonly used in HVAC, industrial, and lab applications.
* Volume (B):#Incorrect. Volume is measured using flow meters or tanks.
* Distance (C):#Incorrect. Distance is measured using rulers or lasers.
* Voltage (D):#Incorrect. Voltage is measured using voltmeters.
Thus, the correct answer isA. Pressure.
NEW QUESTION # 36
An air-conditioning unit delivers 10,000 kJ/h (thermal cooling). The equipment uses single-phase electrical power at 220-volt and 5.25 amps with a power factor of 100%. Calculate the coefficient of performance (COP).
- A. 13.2
- B. 3.2
- C. 2.4
- D. 16.1
- E. 6.2
Answer: B
Explanation:
NEW QUESTION # 37
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